Adding items to the beginning of a linked list
void push(node_t ** head, int val) {
node_t * new_node;
new_node = (node_t *) malloc(sizeof(node_t));
new_node->val = val;
new_node->next = *head;
*head = new_node;
}Adding items to the beginning of a linked list
void push(node_t ** head, int val) {
node_t * new_node;
new_node = (node_t *) malloc(sizeof(node_t));
new_node->val = val;
new_node->next = *head;
*head = new_node;
}adding a node at the beginning of a linked list in c
/*
* STEPS TO INSERT A NODE AT THE BEGINNING OF A LINKED LIST
* 1. Create a new node
* 2. Make the new node point to the head
* 3. Asign the new node to the head
*/
#include <stdlib.h>
#include <string.h>
#include <stdio.h>
/**
* USED THIS STRUCT IN THIS PROGRAM
* struct list_s - singly linked list
* @str: string - (malloc'ed string)
* @len: length of the string
* @next: points to the next node
*/
typedef struct list_s
{
char *str;
unsigned int len;
struct list_s *next;
} list_t;
/**
* add_node - adds a new node at the beginning
* of a list_t list.
* @head: A pointer to the head of the list_t list.
* @str: The string to be added to the list_t list.
*
* Return: If the function fails - NULL.
* Otherwise - the address of the new element.
*/
list_t *add_node(list_t **head, const char *str)
{
char *dup;
int len;
list_t *new;
new = malloc(sizeof(list_t));
if (new == NULL)
return (NULL);
dup = strdup(str);
if (dup == NULL)
{
free(new);
return (NULL);
}
for (len = 0; str[len];)
len++;
new->str = dup;
new->len = len;
new->next = *head;
*head = new;
return (new);
}Copyright © 2021 Codeinu
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