swap of two numbers without using third variable
a=20;
b=40;
a=a+b;
b=a-b;
a=a-b;
swap of two numbers without using third variable
a=20;
b=40;
a=a+b;
b=a-b;
a=a-b;
swap 2 numbers without using 3rd variable
a=10;
b=20;
a=a+b;//a=30 (10+20)
b=a-b;//b=10 (30-20)
a=a-b;//a=20 (30-10)
how to swap 2 numbers without 3rd variable
int a = 3;
int b = 5;
a = b*a;
b = a/b
a = a/b
swap using third variable
// SWAP USING THIRD VARIBLE
#include <stdio.h>
int main()
{
int var1, var2, temp;
printf("Enter two integersn");
scanf("%d%d", &var1, &var2);
printf("Before SwappingnFirst variable = %dnSecond variable = %dn", var1, var2);
temp = var1;
var1 = var2;
var2 = temp;
printf("After SwappingnFirst variable = %dnSecond variable = %dn", var1, var2);
return 0;
}
swap two numbers without using third variable
var a=window.prompt('enter a number')var b=window.prompt('enter a number')var a=a+b;var b=a-b;var a=a-b;console.log ("value of a is",a);console.log('value of b is',b);
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