Answers for "swap two numbers without using third variable"

4

swap 2 numbers without using 3rd variable

a=10;
b=20;
a=a+b;//a=30 (10+20)    
b=a-b;//b=10 (30-20)    
a=a-b;//a=20 (30-10)
Posted by: Guest on May-16-2021
1

swap two variables without temporary java

import java.*; 
  
class noTemp { 
  
    public static void main(String a[]) 
    { 
        int x = 10; 
        int y = 5; 
        x = x + y; 
        y = x - y; 
        x = x - y; 
        System.out.println("After swaping:"
                           + " x = " + x + ", y = " + y); 
    } 
}
Posted by: Guest on January-22-2021
1

swapping without third variable use

x = x + y
y = x - y
x = x - y
Posted by: Guest on June-10-2021
2

swap without using third variable

// SWAPPING WITHOUT USING THIRD VARIABLE
#include<stdio.h>  
 int main()    
{    
int a=10, b=20;      
printf("Before swap a=%d b=%d",a,b);      
a=a+b;//a=30 (10+20)    
b=a-b;//b=10 (30-20)    
a=a-b;//a=20 (30-10)    
printf("\nAfter swap a=%d b=%d",a,b);    
return 0;  
}   
Posted by: Guest on March-03-2021
1

Write a program to show swap of two numbers without using third variable.

#include<stdio.h>  
 int main()    
{    
int a=10, b=20;      
printf("Before swap a=%d b=%d",a,b);      
a=a+b;//a=30 (10+20)    
b=a-b;//b=10 (30-20)    
a=a-b;//a=20 (30-10)    
printf("\nAfter swap a=%d b=%d",a,b);    
return 0;  
}
Posted by: Guest on February-02-2021
0

swap two numbers without using third variable

var a=window.prompt('enter a number')var b=window.prompt('enter a number')var a=a+b;var b=a-b;var a=a-b;console.log ("value of a is",a);console.log('value of b is',b);
Posted by: Guest on June-28-2021

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