Merge sort in c++
#include <iostream> using namespace std; void merge(int arr[], int l, int m, int r) { int n1 = m - l + 1; int n2 = r - m; int L[n1], R[n2]; for (int i = 0; i < n1; i++) L[i] = arr[l + i]; for (int j = 0; j < n2; j++) R[j] = arr[m + 1 + j]; int i = 0; int j = 0; int k = l; while (i < n1 && j < n2) { if (L[i] <= R[j]) { arr[k] = L[i]; i++; } else { arr[k] = R[j]; j++; } k++; } while (i < n1) { arr[k] = L[i]; i++; k++; } while (j < n2) { arr[k] = R[j]; j++; k++; } } void mergeSort(int arr[],int l,int r){ if(l>=r){ return; } int m = (l+r-1)/2; mergeSort(arr,l,m); mergeSort(arr,m+1,r); merge(arr,l,m,r); } void printArray(int A[], int size) { for (int i = 0; i < size; i++) cout << A[i] << " "; } int main() { int arr[] = { 12, 11, 13, 5, 6, 7 }; int arr_size = sizeof(arr) / sizeof(arr[0]); cout << "Given array is \n"; printArray(arr, arr_size); mergeSort(arr, 0, arr_size - 1); cout << "\nSorted array is \n"; printArray(arr, arr_size); return 0; }