gcd in c++
#include<iostream>
using namespace std;
long long gcd(long long a, long long b)
{
if (b == 0)
return a;
return gcd(b, a % b);
}
int main()
{
long long a,b;
cin>>a>>b;
cout<<gcd(a,b);
}gcd in c++
#include<iostream>
using namespace std;
long long gcd(long long a, long long b)
{
if (b == 0)
return a;
return gcd(b, a % b);
}
int main()
{
long long a,b;
cin>>a>>b;
cout<<gcd(a,b);
}gcd function in c++
int gcd(int a, int b)
{
// Everything divides 0
if (a == 0)
return b;
if (b == 0)
return a;
// base case
if (a == b)
return a;
// a is greater
if (a > b)
return gcd(a-b, b);
return gcd(a, b-a);
}gcd in c++
#include<iostream>
using namespace std;
int euclid_gcd(int a, int b) {
if(a==0 || b==0) return 0;
int dividend = a;
int divisor = b;
while(divisor != 0){
int remainder = dividend%divisor;
dividend = divisor;
divisor = remainder;
}
return dividend;
}
int main()
{
cout<<euclid_gcd(0,7)<<endl;
cout<<euclid_gcd(55,78)<<endl;
cout<<euclid_gcd(105,350)<<endl;
cout<<euclid_gcd(350,105)<<endl;
return 0;
}gcd program in c
#include <stdio.h>
int main()
{
int t, n1, n2, gcd;
scanf("%d", &t); // Test Case Input
while (t--)
{
scanf("%d %d", &n1, &n2);// Taking numbers input
if (n2 > n1)
{
gcd = n1;
n1 = n2;
n2 = gcd;
}
while (n1 % n2 != 0)
{
gcd = n2;
n2 = n1 % n2;
n1 = gcd;
}
// n2 is our gcd
printf("GCD: %d\n", n2);
}
return 0;
}Copyright © 2021 Codeinu
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