Answers for "square root c++"

C++
17

sqrt in c++

#include <cmath>
sqrt(x);
Posted by: Guest on June-20-2020
4

sqrt cpp

#include <math.h>

//get square root of a number "b"
int main(){
  	int a = 2; //declare number you want to take square root of
  	int sqrtNum = sqrt (a); //assign the sqrt value to a variable
  	cout << sqrtNum << endl;
	return 0;
}
Posted by: Guest on June-19-2020
1

Finding a square-root of a number in C++

#include <cmath> //library for the function 

sqrt(variable);
Posted by: Guest on October-01-2021
1

square root c++

#include <stdlib.h>
#include <stdio.h>
#include <math.h>

/*
square root of a number
*/

int main(){
float num, raiz;
printf("enter a number: \t");
scanf("%f",&num);
raiz = sqrt(num);
printf("The square root of %f is: %f.\n", num, raiz);
system("pause");
return 0;    
}
Posted by: Guest on April-16-2021
0

sqrt in c++

#include <iostream>
#include <cmath>
using namespace std;

int main()
{
	int x = 625;
	int result = sqrt(x);
	cout << "Square root of " << x << " is " << result << endl;
	return 0;
}
Posted by: Guest on June-05-2021
0

how to make a square root function in c++ without stl

#include <math.h>

double sqrt(double x) {
    if (x <= 0)
        return 0;       // if negative number throw an exception?
    int exp = 0;
    x = frexp(x, &exp); // extract binary exponent from x
    if (exp & 1) {      // we want exponent to be even
        exp--;
        x *= 2;
    }
    double y = (1+x)/2; // first approximation
    double z = 0;
    while (y != z) {    // yes, we CAN compare doubles here!
        z = y;
        y = (y + x/y) / 2;
    }
    return ldexp(y, exp/2); // multiply answer by 2^(exp/2)
}
Posted by: Guest on June-05-2021

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