c++ sort array of ints
// C++ program to demonstrate default behaviour of
// sort() in STL.
#include <bits/stdc++.h>
using namespace std;
int main()
{
int arr[] = {1, 5, 8, 9, 6, 7, 3, 4, 2, 0};
int n = sizeof(arr)/sizeof(arr[0]);
sort(arr, arr+n);
cout << "\nArray after sorting using "
"default sort is : \n";
for (int i = 0; i < n; ++i)
cout << arr[i] << " ";
return 0;
}how to sort an array in c++
#include <bits/stdc++.h>
using namespace std;
#define size(arr) sizeof(arr)/sizeof(arr[0]);
int main(){
int a[5] = {5, 2, 6,3 ,5};
int n = size(a);
sort((a), a + n);
for(int i = 0; i < n; i++){
cout << a[i];
}
return 0;
}c++ sort
int arr[]= {2,3,5,6,1,2,3,6,10,100,200,0,-10};
int n = sizeof(arr)/sizeof(int);
sort(arr,arr+n);
for(int i: arr)
{
cout << i << " ";
}c++ sort
#include<bits/stdc++.h>
vector<int> v = { 6,1,4,5,2,3,0};
sort(v.begin() , v.end()); // {0,1,2,3,4,5,6} sorts ascending
sort(v.begin(), v.end(), greater<int>()); // {6,5,4,3,2,1,0} sorts descendingCopyright © 2021 Codeinu
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