max three values c++
int a = 1;
int b = 2;
int c = 3;
int m = std::max({a, b, c});max three values c++
int a = 1;
int b = 2;
int c = 3;
int m = std::max({a, b, c});find min and max in array c++
#include<iostream>
using namespace std;
public void getMax_MinValue(int arr[])
{
int max, min;
max = arr[0];
min = arr[0];
for (int i = 0; i < sizeof(arr); i++)
{
if (max < arr[i])
max = arr[i];
else if (min > arr[i])
min = arr[i];
}
cout << "Largest element : " << max;
cout << "Smallest element : " << min;
}find max value in array c++
cout << " max element is: " << *max_element(array , array + n) << endl;max element in array c++ stl
*max_element (first_index, last_index);
ex:- for an array arr of size n
*max_element(arr, arr + n);how to get the largest number in a c++ array
#include <iostream>
using namespace std;
int main(){
//n is the number of elements in the array
int n, largest;
int num[50];
cout<<"Enter number of elements you want to enter: ";
cin>>n;
/* Loop runs from o to n, in such a way that first
* element entered by user is stored in num[0], second
* in num[1] and so on.
*/
for(int i = 0; i < n; i++) {
cout<<"Enter Element "<<(i+1)<< ": ";
cin>>num[i];
}
// Storing first array element in "largest" variable
largest = num[0];
for(int i = 1;i < n; i++) {
/* We are comparing largest variable with every element
* of array. If there is an element which is greater than
* largest variable value then we are copying that variable
* to largest, this way we have the largest element copied
* to the variable named "largest" at the end of the loop
*
*/
if(largest < num[i])
largest = num[i];
}
cout<<"Largest element in array is: "<<largest;
return 0;
}find the maximum number from an int Array
---without sort method---
public static int maxValue( int[] n ) {
int max = Integer.MIN_VALUE;
for(int each: n)
if(each > max)
max = each;
return max;
---with sort method---
public static int maxValue( int[] n ) {
Arrays.sort( n );
return n [ n.lenth-1 ];
}Copyright © 2021 Codeinu
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