Answers for "binary tree search"

binary tree search

/* This is just the seaching function you need to write the required code.
	Thank you. */

void searchNode(Node *root, int data)
{
    if(root == NULL)
    {
        cout << "Tree is empty\n";
        return;
    }

    queue<Node*> q;
    q.push(root);

    while(!q.empty())
    {
        Node *temp = q.front();
        q.pop();

        if(temp->data == data)
        {
            cout << "Node found\n";
            return;
        }

        if(temp->left != NULL)
            q.push(temp->left);
        if(temp->right != NULL)
            q.push(temp->right);
    }

    cout << "Node not found\n";
}

binary search tree

Binary Search Tree is a node-based binary tree data structure which has the following properties:

The left subtree of a node contains only nodes with keys lesser than the node’s key.
The right subtree of a node contains only nodes with keys greater than the node’s key.
The left and right subtree each must also be a binary search tree.

Searching in Binary Search Tree

public class BinarySearchTree {

    public class Node {
        //instance variable of Node class
        public int data;
        public Node left;
        public Node right;

        //constructor
        public Node(int data) {
            this.data = data;
            this.left = null;
            this.right = null;
        }
    }
    
    // instance variable
    public Node root;

    // constructor for initialise the root to null BYDEFAULT
    public BinarySearchTree() {
        this.root = null;
    }

    // insert method to insert the new Date
    public void insert(int newData) {
        this.root = insert(root, newData);
    }

    public Node insert(Node root, int newData) {
        // Base Case: root is null or not
        if (root == null) {
            // Insert the new data, if root is null.
            root = new Node(newData);
            // return the current root to his sub tree
            return root;
        }
        // Here checking for root data is greater or equal to newData or not
        else if (root.data >= newData) {
            // if current root data is greater than the new data then now process the left sub-tree
            root.left = insert(root.left, newData);
        } else {
            // if current root data is less than the new data then now process the right sub-tree
            root.right = insert(root.right, newData);
        }
        return root;
    }

    // method for search the data , is data is present or not in the tree ?
    public boolean search(int data) {
        return search(this.root, data);
    }

    private boolean search(Node root, int data) {
        if (root == null) {
            return false;
        } else if (root.data == data) {
            return true;
        } else if (root.data > data) {
            return search(root.left, data);
        }
        return search(root.right, data);
    }

    //Traversal
    public void preorder() {
        preorder(root);
        System.out.println();
    }

    public void preorder(Node root) {
        if (root == null) {
            return;
        }
        System.out.print(root.data + " ");
        preorder(root.left);
        preorder(root.right);
    }

    public static void main(String[] args) {
        // Creating the object of BinarySearchTree class
        BinarySearchTree bst = new BinarySearchTree();
        // call the method insert
        bst.insert(8);
        bst.insert(5);
        bst.insert(9);
        bst.insert(3);
        bst.insert(7);
        bst.preorder();
        System.out.println(bst.search(7));
        
    }
}

binary search tree

# Driver Code 
arr = [ 2, 3, 4, 10, 40 ] 
x = 10
  
# Function call 
result = binarySearch(arr, 0, len(arr)-1, x) 
  
if result != -1: 
    print ("Element is present at index % d" % result) 
else: 
    print ("Element is not present in array")