sum of n natural numbers in python
# Sum of natural numbers up to num
num = 16
if num < 0:
print("Enter a positive number")
else:
sum = 0
# use while loop to iterate until zero
while(num > 0):
sum += num
num -= 1
print("The sum is", sum)sum of all n integers
Sum of n integers 1 + 2 + 3 + ... + n = n * (n + 1) / 2sum of n natural numbers
#include<bits/stdc++.h>
using namespace std;
int main()
{
int n;
int sum=0;
cin>>n;
for(int i=1;i<=n;i++)
{
sum+=i;
}
cout<<sum<<" ";
cout<<endl;
return 0;
}formula for sum of n numbers
Sum of the First n Natural Numbers. We prove the formula 1+ 2+ ... + n = n(n+1) / 2, for n a natural numbersum of n natural numbers in c
int addNumbers(int n)
{
int count, sum = 0;
for(count=1; count <= n; count++)
{
sum = sum + count;
}
return sum;
}Copyright © 2021 Codeinu
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