c++ sum of even and odd numbers
//given the fact that it takes n of number
void sumEvenAndOdd(){
int n=0 , evenSum=0 , oddSum=0;
int numbers[Size];
cout<<"enters the number(N) of integers\n";
cin>>Size;
cout<<"Enter "<<Size<<" number/s:\n";
for(int i =0 ;i< Size ; ++i){
cin>>numbers[i];
}
for(int i =0 ;i<Size ; ++i){
if(numbers[i]%2 ==0){
evenSum += numbers[i];
}
else{
oddSum += numbers[i];
}
}
cout<<"the sum of even numbers is : "<<evenSum <<"\nthe sum of odd numbers is :"<<oddSum<<endl;
}