Answers for "templates c++"

C++
17

c++ template function

template <class T>
void swap(T & lhs, T & rhs)
{
 T tmp = lhs;
 lhs = rhs;
 rhs = tmp;
}
Posted by: Guest on March-14-2020
6

function template

template <class T>
void swap(T & lhs, T & rhs)
{
 T tmp = lhs;
 lhs = rhs;
 rhs = tmp;
}

void main()
{
  int a = 6;
  int b = 42;
  swap<int>(a, b);
  printf("a=%d, b=%d\n", a, b);
  
  // Implicit template parameter deduction
  double f = 5.5;
  double g = 42.0;
  swap(f, g);
  printf("f=%f, g=%f\n", f, g);
}

/*
Output:
a=42, b=6
f=42.0, g=5.5
*/
Posted by: Guest on April-16-2020
4

c++ template

#include <iostream>
using namespace std;

template <typename T>
void Swap(T &n1, T &n2)
{
	T temp;
	temp = n1;
	n1 = n2;
	n2 = temp;
}

int main()
{
	int i1 = 1, i2 = 2;
	float f1 = 1.1, f2 = 2.2;
	char c1 = 'a', c2 = 'b';

	cout << "Before passing data to function template.\n";
	cout << "i1 = " << i1 << "\ni2 = " << i2;
	cout << "\nf1 = " << f1 << "\nf2 = " << f2;
	cout << "\nc1 = " << c1 << "\nc2 = " << c2;

	Swap(i1, i2);
	Swap(f1, f2);
	Swap(c1, c2);

        cout << "\n\nAfter passing data to function template.\n";
	cout << "i1 = " << i1 << "\ni2 = " << i2;
	cout << "\nf1 = " << f1 << "\nf2 = " << f2;
	cout << "\nc1 = " << c1 << "\nc2 = " << c2;

	return 0;
}
Posted by: Guest on August-14-2020
1

template in c++

// template function
template <class T>
T Large(T n1, T n2)
{
	return (n1 > n2) ? n1 : n2;
}
Posted by: Guest on October-29-2020
2

c++ template

// function template
#include <iostream>
using namespace std;

template <class T>
T GetMax (T a, T b) {
  T result;
  result = (a>b)? a : b;
  return (result);
}

int main () {
  int i=5, j=6, k;
  long l=10, m=5, n;
  k=GetMax<int>(i,j);
  n=GetMax<long>(l,m);
  cout << k << endl;
  cout << n << endl;
  return 0;
}
Posted by: Guest on December-15-2020
0

templates c++

template  < typename  T > 
inline  T  max ( T  a ,  T  b )  { 
    return  a  >  b  ?  a  :  b ; 
}

int  main () 
{ 
    // Isso chamará max <int> por dedução implícita do argumento. 
    std :: cout  <<  max ( 3 ,  7 )  <<  std :: endl ;

    // Isso chamará max <double> por dedução implícita do argumento. 
    std :: cout  <<  max ( 3.0 ,  7.0 )  <<  std :: endl ;

    // Isso depende do compilador. Alguns compiladores lidam com isso definindo uma 
    função de 
    modelo // como double max <double> (double a, double b) ;, enquanto em alguns compiladores // precisamos convertê-lo explicitamente, como std :: cout << max <double> (3,7,0); 
    std :: cout  <<  max ( 3 ,  7.0 )  <<  std :: endl ; 
    std :: cout  <<  max < double > ( 3 ,  7.0 )  <<  std :: endl ; 
    return  0 ; 
}
Posted by: Guest on June-16-2021

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