find last element of an array c++
int arr={1,2,3,4,5,6};
int length=sizeof(arr)/sizeof(int);
int lastElement=aar[length-1];find last element of an array c++
int arr={1,2,3,4,5,6};
int length=sizeof(arr)/sizeof(int);
int lastElement=aar[length-1];c++ get last element in array
#include<iostream>
/*To get the last element of the array we first get the size
of the array by using sizeof(). Unfortunately, this gives
us the size of the array in bytes. To fix this, we divide
the size (in bytes) by the size of the data type in the array.
In our case, this would be int, so we divide sizeof(array)
by sizeof(int). Since arrays start from 0 and not 1 we
subtract one to get the last element.
-yegor*/
int array[5] = { 1, 2, 3, 4, 5 };
printf("Last Element of Array: %d", array[(sizeof(array)/sizeof(int))-1]);c++ last element of array
int arr[10];
int len = sizeof(arr) / sizeof(arr[0]);get the last element of an array c++
// C++ Program to print first and last element in an array
#include <iostream>
using namespace std;
int main()
{
int arr[] = { 4, 5, 7, 13, 25, 65, 98 };
int f, l, n;
n = sizeof(arr) / sizeof(arr[0]);
f = arr[0];
l = arr[n - 1];
cout << "First element: " << f << endl;
cout << "Last element: " << l << endl;
return 0;
}Copyright © 2021 Codeinu
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