Answers for "articulation point in a graph"

C++
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articulation point in a graph

//Articulation point is a point in the graph on whose removal graph is broken into components
//striver graph series
//Do check u__code on youtube
#include<bits/stdc++.h>
using namespace std;
void addedge(vector<int>adj[],int u,int v)
{
    adj[u].push_back(v);
    adj[v].push_back(u);
}
void dfs(int node,int parent,vector<int>&visited,vector<int>&low,vector<int>&tin,vector<int>adj[],int timer,vector<int>&isarticulate)
{
    visited[node]=1;
    low[node]=tin[node]=timer++;
    int child=0;
    for(auto it:adj[node])
    {
        if(it==parent)
            continue;
        if(!visited[it])
        {
            dfs(it,node,visited,low,tin,adj,timer,isarticulate);
            low[node]=min(low[node],low[it]);
            if(low[it]>=tin[node]&&parent!=-1)
            {
                isarticulate[node]=1;
            }
        }
        else
        {
            low[node]=min(low[node],tin[it]);
        }
    }
    if(parent==-1&&child>1)
        isarticulate[node]=1;
}
int main()
{
    int vertex,edges;
    cout<<"ENTER THE VERTEX AND EDGES:"<<endl;
    cin>>vertex>>edges;
    vector<int>adj[vertex];
    int a,b;
    cout<<"ENTER THE LINKS:"<<endl;
    for(int i=0;i<edges;i++)
    {
        cin>>a>>b;
        addedge(adj,a,b);
    }
    vector<int>tin(vertex,-1);
    vector<int>low(vertex,-1);
    vector<int>visited(vertex,0);
    vector<int>isarticulate(vertex,0);
    int timer=0;
    for(int i=0;i<vertex;i++)
    {
        if(!visited[i])
        {
            dfs(i,-1,visited,low,tin,adj,timer,isarticulate);
        }
    }
    for(int i=0;i<vertex;i++)
    {
        if(isarticulate[i]==1)
        {
            cout<<i<<" ";
        }
    }
    return 0;
}
Posted by: Guest on August-31-2021

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