Answers for "check a number is perfect square or not"

program to tell if a number is a perfect square

import math

# Taking the input from user
number = int(input("Enter the Number"))

root = math.sqrt(number)
if int(root + 0.5) ** 2 == number:
    print(number, "is a perfect square")
else:
    print(number, "is not a perfect square")

how to check sqrt of number is integer c++

bool isPerfectSquare(long double x) 
{   
  // Find floating point value of  
  // square root of x. 
  long double sr = sqrt(x); 
  
  // If square root is an integer 
  return ((sr - floor(sr)) == 0); 
}