check if a number is perfect cube in python
x = int(input())
print(int(round(x ** (1. / 3))) ** 3 == x)check if a number is perfect cube in python
x = int(input())
print(int(round(x ** (1. / 3))) ** 3 == x)check if number is perfect cube python
def is_cube(n):
guess = n**(1.0/3.0)
iguess = int(guess)
if iguess * iguess * iguess == n:
print(True, "it's cubed root is", iguess)
return
iguess = iguess + 1
if iguess * iguess * iguess == n:
print(True, "it's cubed root is", iguess)
return
print(False, "it's cubed root is", guess)
is_cube(9) # No
is_cube(27) # Yeshow to check if a number is a perfect square python
import math
# Taking the input from user
number = int(input("Enter the Number"))
root = math.sqrt(number)
if int(root + 0.5) ** 2 == number:
print(number, "is a perfect square")
else:
print(number, "is not a perfect square")Copyright © 2021 Codeinu
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