maximum subarray solution leetcode
def approach3(nums):
ans = nums[0]
subarr_sum = nums[0]
for i in range(1, len(nums)):
subarr_sum = max(nums[i], nums[i] + subarr_sum)
ans = max(ans, subarr_sum)
return ans
maximum subarray solution leetcode
def approach3(nums):
ans = nums[0]
subarr_sum = nums[0]
for i in range(1, len(nums)):
subarr_sum = max(nums[i], nums[i] + subarr_sum)
ans = max(ans, subarr_sum)
return ans
find longest subarray by sum
def max_length(s, k):
current = []
max_len = -1 # returns -1 if there is no subsequence that adds up to k.
for i in s:
current.append(i)
while sum(current) > k: # Shrink the array from the left, until the sum is <= k.
current = current[1:]
if sum(current) == k:
max_len = max(max_len, len(current))
return max_len
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