maximum subarray solution leetcode
def approach3(nums):
ans = nums[0]
subarr_sum = nums[0]
for i in range(1, len(nums)):
subarr_sum = max(nums[i], nums[i] + subarr_sum)
ans = max(ans, subarr_sum)
return ansmaximum subarray solution leetcode
def approach3(nums):
ans = nums[0]
subarr_sum = nums[0]
for i in range(1, len(nums)):
subarr_sum = max(nums[i], nums[i] + subarr_sum)
ans = max(ans, subarr_sum)
return ansCopyright © 2021 Codeinu
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