generate parentheses leetcode solution
public List<String> generateParenthesis(int n) {
ArrayList<String> result = new ArrayList<String>();
ArrayList<Integer> diff = new ArrayList<Integer>();
result.add("");
diff.add(0);
for (int i = 0; i < 2 * n; i++) {
ArrayList<String> temp1 = new ArrayList<String>();
ArrayList<Integer> temp2 = new ArrayList<Integer>();
for (int j = 0; j < result.size(); j++) {
String s = result.get(j);
int k = diff.get(j);
if (i < 2 * n - 1) {
temp1.add(s + "(");
temp2.add(k + 1);
}
if (k > 0 && i < 2 * n - 1 || k == 1 && i == 2 * n - 1) {
temp1.add(s + ")");
temp2.add(k - 1);
}
}
result = new ArrayList<String>(temp1);
diff = new ArrayList<Integer>(temp2);
}
return result;
}