Answers for "deserialize json to dynamic object c#"

C#
2

json.net deserialize dynamic

dynamic d = JObject.Parse("{number:1000, str:'string', array: [1,2,3,4,5,6]}");

Console.WriteLine(d.number);
Console.WriteLine(d.str);
Console.WriteLine(d.array.Count);
Posted by: Guest on May-08-2021

Code answers related to "deserialize json to dynamic object c#"

C# Answers by Framework

Browse Popular Code Answers by Language