Answers for "c# object to xml"

C#
1

string to xml c#

string test = "<body><head>test header</head></body>";

XmlDocument xmltest = new XmlDocument();
xmltest.LoadXml(test);

XmlNodeList elemlist = xmltest.GetElementsByTagName("head");

string result = elemlist[0].InnerXml; 

//result -> "test header"
Posted by: Guest on December-21-2020
0

convert object to xml c# example code

public class StringUtil
{
  
      public static string Serialize(object dataToSerialize)
        {
            if(dataToSerialize==null) return null;

            using (StringWriter stringwriter = new System.IO.StringWriter())
            {
                var serializer = new XmlSerializer(dataToSerialize.GetType());
                serializer.Serialize(stringwriter, dataToSerialize);
                return stringwriter.ToString();
            }
        }

        public static T Deserialize<T>(string xmlText)
        {
            if(String.IsNullOrWhiteSpace(xmlText)) return default(T);

            using (StringReader stringReader = new System.IO.StringReader(xmlText))
            {
                var serializer = new XmlSerializer(typeof(T));
                return (T)serializer.Deserialize(stringReader);
            }
        }
}

//Note 
//StringUtil.Serialize(ObjClass); >> return xml
//StringUtil.Deserialize<ObjClass>(str_xml); >> return object
Posted by: Guest on January-07-2021
0

c# serialize to xml

XmlSerializer xsSubmit = new XmlSerializer(typeof(MyObject));
 var subReq = new MyObject();
 var xml = "";

 using(var sww = new StringWriter())
 {
     using(XmlWriter writer = XmlWriter.Create(sww))
     {
         xsSubmit.Serialize(writer, subReq);
         xml = sww.ToString(); // Your XML
     }
 }
Posted by: Guest on August-03-2020
0

xmldocument to c# object

void Main()
{
   String aciResponseData = "<?xml version="1.0" encoding="UTF-8"?><tag><bar>test</bar></tag>";
   using(TextReader sr = new StringReader(aciResponseData))
   {
        var serializer = new System.Xml.Serialization.XmlSerializer(typeof(MyClass));
        MyClass response =  (MyClass)serializer.Deserialize(sr);
        Console.WriteLine(response.bar);
   }
}

[System.Xml.Serialization.XmlRoot("tag")]
public class MyClass
{
   public String bar;
}
Posted by: Guest on December-21-2020

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