Answers for "generate 3 random numbers that add up to another number c#"

C#
2

c# two different random numbers

Random random = new Random();
int randomNumber1 = random.Next(0, 300);
int randomNumber2 = random.Next(0, 300);
//...
Posted by: Guest on July-24-2020
0

random 6 digit number c#

Random generator = new Random();
    String r = generator.Next(0, 1000000).ToString("D6");
Posted by: Guest on December-16-2021

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