Prime factors of a number
public List<Integer> factorsOf(int n) {
ArrayList<Integer> factors = new ArrayList<>();
for (int d = 2; n > 1; d++)
for (; n % d == 0; n /= d)
factors.add(d);
return factors;
}Prime factors of a number
public List<Integer> factorsOf(int n) {
ArrayList<Integer> factors = new ArrayList<>();
for (int d = 2; n > 1; d++)
for (; n % d == 0; n /= d)
factors.add(d);
return factors;
}prime factors of a number
public static List<int> PrimeFactors(int n)
{
if (n == 1)
{
return null;
}
var list = new List<int>();
if (n % 2 == 0)
{
list.Add(2);
while (n % 2 == 0)
{
n /= 2;
}
}
for (int i = 3; i <= Math.Sqrt(n); i += 2)
{
if (n % i == 0)
{
list.Add(i);
while (n % i == 0)
{
n /= i;
}
}
}
if (n > 2)
list.Add(n);
return list;
}Copyright © 2021 Codeinu
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