Answers for "w3schools javascript odd and even number"

Odd number function in javascript

let arr = [1,2,3,4,5,6,7,8,9,10,11,12]

let odds = arr.filter(n => n%2)

console.log(odds)

Even number function in javascript

function isEven(numbers) {
    if (numbers % 2 == 0) {
        return true;
    }
    return false;

}
var input = 22;
var result = isEven(input);
console.log(result)
//Outpur: true

odd or even js

for(let count =0; count<=100;count++){
 count%2==0? console.log(`${count} is even`):console.log(`${count} is odd`);
 ;
}