Answers for "golang map"

Go
3

go remove from map

m := map[string]string{"key1": "val1", "key2": "val2"}
delete(m, "key1")
Posted by: Guest on April-10-2020
5

initialize map in golang

// By default maps in Go behaves like a default dictionary in python
m := make(map[string]int)

m["Dio"] = 3
m["Jonathan"] = 1
Posted by: Guest on May-11-2020
2

length of map golang

package main
 
import "fmt"
 
func main() {
    var employee = make(map[string]int)
    employee["Mark"] = 10
    employee["Sandy"] = 20
 
    // Empty Map
    employeeList := make(map[string]int)
 
    fmt.Println(len(employee))     // 2
    fmt.Println(len(employeeList)) // 0
}
Posted by: Guest on August-27-2020
1

golang map

//map in go is a built in type implementaiton of has table
//create an empty map
myMap := make(map[string]string)
//insert key-value pair in map
myMap["key"] = "value"
//read from map
value, ok := myMap["key"]
//delete from map
delete(myMap, "key")
Posted by: Guest on September-07-2021
3

go add to map

m := make(map[string]int)
m["numberOne"] = 1
m["numberTwo"] = 2
Posted by: Guest on April-10-2020
2

golang map

package main

import (
	"fmt"
)

type User struct {
	Name string
	Age  int
}

func main() {

	var person = map[string]string{
		"name": "john doe",
		"age":  "23",
	}

	var profile = make(map[string]string)
	profile["name"] = "jane doe"
	profile["age"] = "23"

	var user = make(map[string]interface{})

	user["name"] = "peter parker"
	user["age"] = 30

	var users = []map[string]interface{}{
		{"name": "monkey d lufy", "age": 19},
		{"name": "trafagar d law", "age": 23},
		{"name": "nico robin", "age": 20},
	}

	var userStruct = map[string]User{
		"name": {Name: "Monkey D Lufy"},
		"age":  {Age: 19},
	}

	fmt.Println(person)
	fmt.Println(profile)
	fmt.Println(user)
	fmt.Println(users)
	fmt.Println(userStruct)
}
Posted by: Guest on March-10-2021

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