Answers for "binary search tree using go"

Go
1

binary tree in golang

// Binary Tree in Golang
package main
  
import (
    "fmt"
    "os"
    "io"
)
  
type BinaryNode struct {
    left  *BinaryNode
    right *BinaryNode
    data  int64
}
  
type BinaryTree struct {
    root *BinaryNode
}
  
func (t *BinaryTree) insert(data int64) *BinaryTree {
    if t.root == nil {
        t.root = &BinaryNode{data: data, left: nil, right: nil}
    } else {
        t.root.insert(data)
    }
    return t
}
  
func (n *BinaryNode) insert(data int64) {
    if n == nil {
        return
    } else if data <= n.data {
        if n.left == nil {
            n.left = &BinaryNode{data: data, left: nil, right: nil}
        } else {
            n.left.insert(data)
        }
    } else {
        if n.right == nil {
            n.right = &BinaryNode{data: data, left: nil, right: nil}
        } else {
            n.right.insert(data)
        }
    }   
}
  
func print(w io.Writer, node *BinaryNode, ns int, ch rune) {
    if node == nil {
        return
    }
  
    for i := 0; i < ns; i++ {
        fmt.Fprint(w, " ")
    }
    fmt.Fprintf(w, "%c:%vn", ch, node.data)
    print(w, node.left, ns+2, 'L')
    print(w, node.right, ns+2, 'R')
}
  
func main() {
    tree := &BinaryTree{}
    tree.insert(100).
        insert(-20).
        insert(-50).
        insert(-15).
        insert(-60).
        insert(50).
        insert(60).
        insert(55).
        insert(85).
        insert(15).
        insert(5).
        insert(-10)
    print(os.Stdout, tree.root, 0, 'M')
}
Posted by: Guest on May-25-2020
0

golang binary search tree bst

package main

import "fmt"

type bstnode struct {
    value int
    left  *bstnode
    right *bstnode
}

type bst struct {
    root *bstnode
}

func (b *bst) reset() {
    b.root = nil
}

func (b *bst) insert(value int) {
    b.insertRec(b.root, value)
}

func (b *bst) insertRec(node *bstnode, value int) *bstnode {
    if b.root == nil {
        b.root = &bstnode{
            value: value,
        }
        return b.root
    }
    if node == nil {
        return &bstnode{value: value}
    }
    if value <= node.value {
        node.left = b.insertRec(node.left, value)
    }
    if value > node.value {
        node.right = b.insertRec(node.right, value)
    }
    return node
}

func (b *bst) find(value int) error {
    node := b.findRec(b.root, value)
    if node == nil {
        return fmt.Errorf("Value: %d not found in tree", value)
    }
    return nil
}

func (b *bst) findRec(node *bstnode, value int) *bstnode {
    if node == nil {
        return nil
    }
    if node.value == value {
        return b.root
    }
    if value < node.value {
        return b.findRec(node.left, value)
    }
    return b.findRec(node.right, value)
}

func (b *bst) inorder() {
    b.inorderRec(b.root)
}

func (b *bst) inorderRec(node *bstnode) {
    if node != nil {
        b.inorderRec(node.left)
        fmt.Println(node.value)
        b.inorderRec(node.right)
    }
}

func main() {
    bst := &bst{}
    eg := []int{2, 5, 7, -1, -1, 5, 5}
    for _, val := range eg {
        bst.insert(val)
    }
    fmt.Printf("Printing Inorder:n")
    bst.inorder()
    bst.reset()
    eg = []int{4, 5, 7, 6, -1, 99, 5}
    for _, val := range eg {
        bst.insert(val)
    }
    fmt.Printf("nPrinting Inorder:n")
    bst.inorder()
    fmt.Printf("nFinding Values:n")
    err := bst.find(2)
    if err != nil {
        fmt.Printf("Value %d Not Foundn", 2)
    } else {
        fmt.Printf("Value %d Foundn", 2)
    }
    err = bst.find(6)
    if err != nil {
        fmt.Printf("Value %d Not Foundn", 6)
    } else {
        fmt.Printf("Value %d Foundn", 6)
    }
    err = bst.find(5)
    if err != nil {
        fmt.Printf("Value %d Not Foundn", 5)
    } else {
        fmt.Printf("Value %d Foundn", 5)
    }
    err = bst.find(1)
    if err != nil {
        fmt.Printf("Value %d Not Foundn", 1)
    } else {
        fmt.Printf("Value %d Foundn", 1)
    }
}
Posted by: Guest on May-09-2021

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