throw error java
throw new java.lang.Error("this is very bad");
throw new java.lang.RuntimeException("this is not quite as bad");throw error java
throw new java.lang.Error("this is very bad");
throw new java.lang.RuntimeException("this is not quite as bad");java throw an exception
public static void main(String[] args) {
Scanner kb = new Scanner(System.in);
System.out.println("Enter a number");
try {
double nb1 = kb.nextDouble();
if(nb1<0)
throw new ArithmeticException();
else System.out.println( "result : " + Math.sqrt(nb1) );
} catch (ArithmeticException e) {
System.out.println("You tried an impossible sqrt");
}
}Copyright © 2021 Codeinu
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