java throw an exception
public static void main(String[] args) {
Scanner kb = new Scanner(System.in);
System.out.println("Enter a number");
try {
double nb1 = kb.nextDouble();
if(nb1<0)
throw new ArithmeticException();
else System.out.println( "result : " + Math.sqrt(nb1) );
} catch (ArithmeticException e) {
System.out.println("You tried an impossible sqrt");
}
}