int to binary java
String binary = Integer.toBinaryString(num);
how to get binary value in java
import java.util.*;
class Bin {
//fields
private Double number;
//constructors
public Bin(){
number = 0.0;
}
public Bin(Double num){
number = num;
}
//methods
public ArrayList<String> reverseArrayList(ArrayList<String> alist) {
ArrayList<String> array = new ArrayList<String>();
int x = 0;
int i = alist.size() - 1;
while(x < alist.size()){
array.add(alist.get(i));
i -= 1;
x += 1;
}
return array;
}
//getter methods
public ArrayList<String> getBinVal(){
ArrayList<String> binaryVal = new ArrayList<String>();
ArrayList<String> array = new ArrayList<String>();
Double num = number;
Double sol1, check;
while( num > 0 ) {
sol1 = num/2;
check = sol1 - Math.floor(sol1);
if(check > 0) {
binaryVal.add("1");
num = sol1 - 0.5;
}
else {
binaryVal.add("0");
num = sol1;
}
}
while(binaryVal.size() < 4) {
binaryVal.add("0");
}
array = reverseArrayList(binaryVal);
return array;
}
}
class MainClass {
public static void main(String[] args) {
//add the number in as a command line argument
Double num = Double.valueOf(args[0]);
//create an instance of Bin
Bin value = new Bin(num);
//print the binary value
System.out.println(value.getBinVal());
}
}
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