sum of digits in java
import java.io.*;
public class sd
{
public static void main(String [] args)throws IOException
{
InputStreamReader hi = new InputStreamReader(System.in);
BufferedReader in = new BufferedReader(hi);
System.out.println("Enter the number");
int num=Integer.parseInt(in.readLine());
int sum=0;
while(num>=0)
{
int rem=n;
sum+=rem;
int quo=n/10;
n=quo;
}
System.out.println(sum);
}
}JAVA Program than read an integer and calculate the sum of its digits and write the number of each digit of the sum in English
import java.util.*;
public class Main
{
public static void main(String[] args)
{
int m, n, sum = 0;
Scanner sc=new Scanner(System.in);
System.out.print("Enter the number:");
m = sc.nextInt();
while(m > 0)
{
n = m % 10;
sum = sum + n;
m = m / 10;
}
System.out.println("Sum of Digits:"+sum);
int v,a,r=0;
String[] number = {"zero","one","two","three","four","five","six","seven","eight","nine"};
while(sum!=0)
{
a=sum%10;
r=r*10+a;
sum=sum/10;
}
System.out.print("In Inglish : ");
while(r!=0)
{
v=r%10;
System.out.print(number[v]+" ");
r=r/10;
}
}
}Copyright © 2021 Codeinu
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