Answers for "insertion sort pseudocode"

7

insertion sort java

Insertion program
public class InsertionSortExample
{
   public void sort(int[] arrNum)
   {
      int number = arrNum.length;
      for(int a = 1; a < number; ++a)
      {
         int keyValue = arrNum[a];
         int b = a - 1;
         while(b >= 0 && arrNum[b] > keyValue)
         {
            arrNum[b + 1] = arrNum[b];
            b = b - 1;
         }
         arrNum[b + 1] = keyValue;
      }
   }
   static void displayArray(int[] arrNum)
   {
      int num = arrNum.length;
      for(int a = 0; a < num; ++a)
      {
         System.out.print(arrNum[a] + " ");
      }
      System.out.println();
   }
   public static void main(String[] args)
   {
      int[] arrInput = { 50, 80, 10, 30, 90, 60 };
      InsertionSortExample obj = new InsertionSortExample();
      obj.sort(arrInput);
      displayArray(arrInput);
   }
}
Posted by: Guest on October-23-2020
1

insertion sort

def insertionSort(arr): 
    for i in range(1, len(arr)): 
        key = arr[i] 
        j = i-1
        while j >= 0 and key < arr[j] : 
                arr[j + 1] = arr[j] 
                j -= 1
        arr[j + 1] = key
Posted by: Guest on October-07-2020
2

insertion sort

// Por ter uma complexidade alta,
// não é recomendado para um conjunto de dados muito grande.
// Complexidade: O(n²) / O(n**2) / O(n^2)
// @see https://www.youtube.com/watch?v=TZRWRjq2CAg
// @see https://www.cs.usfca.edu/~galles/visualization/ComparisonSort.html

function insertionSort(vetor) {
    let current;
    for (let i = 1; i < vetor.length; i += 1) {
        let j = i - 1;
        current = vetor[i];
        while (j >= 0 && current < vetor[j]) {
            vetor[j + 1] = vetor[j];
            j--;
        }
        vetor[j + 1] = current;
    }
    return vetor;
}

insertionSort([1, 2, 5, 8, 3, 4])
Posted by: Guest on May-29-2020

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