Answers for "insertion sor"

insertion sort java

Insertion program
public class InsertionSortExample
{
   public void sort(int[] arrNum)
   {
      int number = arrNum.length;
      for(int a = 1; a < number; ++a)
      {
         int keyValue = arrNum[a];
         int b = a - 1;
         while(b >= 0 && arrNum[b] > keyValue)
         {
            arrNum[b + 1] = arrNum[b];
            b = b - 1;
         }
         arrNum[b + 1] = keyValue;
      }
   }
   static void displayArray(int[] arrNum)
   {
      int num = arrNum.length;
      for(int a = 0; a < num; ++a)
      {
         System.out.print(arrNum[a] + " ");
      }
      System.out.println();
   }
   public static void main(String[] args)
   {
      int[] arrInput = { 50, 80, 10, 30, 90, 60 };
      InsertionSortExample obj = new InsertionSortExample();
      obj.sort(arrInput);
      displayArray(arrInput);
   }
}

insertion sort

//I Love Java
import java.util.*;
import java.io.*;
import static java.util.stream.Collectors.toList;
import java.util.stream.*;

public class Insertion_Sort_P {
    public static void main(String[] args) throws IOException {
        BufferedReader buffer = new BufferedReader(new InputStreamReader(System.in));

        List<Integer> arr = Stream.of(buffer.readLine().replaceAll("\\s+$", " ").split(" ")).map(Integer::parseInt)
                .collect(toList());

        insertion_sort(arr);

        System.out.println(arr);
    }

    public static void insertion_sort(List<Integer> arr) {
        for (int i = 1; i <= arr.size() - 1; i++) {
            steps(arr, i);
        }
    }

    public static void steps(List<Integer> arr, int comp) {
        for (int i = 0; i <= comp - 1; i++) {
            if (arr.get(comp) < arr.get(i)) {
                swap(arr, i, comp);
            }
        }
    }

    static void swap(List<Integer> arr, int i, int j) {
        int temp = arr.get(i);
        arr.set(i, arr.get(j));
        arr.set(j, temp);
    }
}

insertion sort

def insertionSort(arr): 
    for i in range(1, len(arr)): 
        key = arr[i] 
        j = i-1
        while j >= 0 and key < arr[j] : 
                arr[j + 1] = arr[j] 
                j -= 1
        arr[j + 1] = key

insertion sort

#include <bits/stdc++.h>

using namespace std; 

void insertionSort(int arr[], int n)  
{  
    int i, temp, j;  
    for (i = 1; i < n; i++) 
    {  
        temp = arr[i];  
        j = i - 1;  

        while (j >= 0 && arr[j] > temp) 
        {  
            arr[j + 1] = arr[j];  
            j = j - 1;  
        }  
        arr[j + 1] = temp;  
    }  
}

int main()  
{  
    int arr[] = { 1,4,2,5,333,3,5,7777,4,4,3,22,1,4,3,666,4,6,8,999,4,3,5,32 };  
    int n = sizeof(arr) / sizeof(arr[0]);  

    insertionSort(arr, n);  

    for(int i = 0; i < n; i++){
        cout << arr[i] << " ";
    }

    return 0;  
}

insertion sort

// Por ter uma complexidade alta,
// não é recomendado para um conjunto de dados muito grande.
// Complexidade: O(n²) / O(n**2) / O(n^2)
// @see https://www.youtube.com/watch?v=TZRWRjq2CAg
// @see https://www.cs.usfca.edu/~galles/visualization/ComparisonSort.html

function insertionSort(vetor) {
    let current;
    for (let i = 1; i < vetor.length; i += 1) {
        let j = i - 1;
        current = vetor[i];
        while (j >= 0 && current < vetor[j]) {
            vetor[j + 1] = vetor[j];
            j--;
        }
        vetor[j + 1] = current;
    }
    return vetor;
}

insertionSort([1, 2, 5, 8, 3, 4])

insertion sort

#insertion sort
def insert(arr):
    for i in range(1,len(arr)):
        while arr[i-1] > arr[i] and i > 0:
            arr[i], arr[i-1] = arr[i-1], arr[i]
            i -= 1 
    return arr 
arr = [23, 55, 12, 99, 66, 33]
print(insert(arr))