Answers for "new random nextint"

3

float random class java

import java.util.Random;
public class Example {
   public static void main(String[] args) {
      Random rd = new Random(); // creating Random object
      System.out.println(rd.nextFloat()); // displaying a random float value between 0.0 and 1.0
   }
}
Posted by: Guest on July-20-2020
0

java random.nextint

public class Random {
  
  public static void main(String[] args) {
    
    Random random = new Random(long seed);
    int bound = 5;
    
    System.out.println(random.nextInt(bound));
    
  }
  
}
/*
Returns a pseudorandom, uniformly distributed int value between
0 (inclusive) and
the specified value 5 (exclusive),
drawn from this random number generator's sequence.
Posted by: Guest on October-10-2020

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