Answers for "optional throw exception if present"

1

optional throw if present

Optional.of(usuarios.findByEmail(usuario.getEmail())).ifPresent(param -> {
      throw new IllegalArgumentException("Only Strings allowed in path parameters.")
    });
Posted by: Guest on October-29-2020
0

stream optional if present anymatch

List<Optional<String>> listOfOptionals = Arrays.asList(
  Optional.empty(), Optional.of("foo"), Optional.empty(), Optional.of("bar"));
Posted by: Guest on December-26-2020

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