how to sort integer array in java
int countOfArray = 5;
int num [] = new int[counfOfArray];
int num[] = [8 , 5 , 9 , 3 , 4];
for (int i = 0; i < countOfArray; i++)
{
for (int j = i + 1; j < countOfArray; j++) {
if (num[i] > num[j])
{
temp = num[i];
num[i] = num[j];
num[j] = temp;
}
}
}java sort int array
// an array of ints
int[] arr = {1, 2, 3, 4, 5, 6};
// an array of reverse sorted ints
int[] arrDesc = Arrays.stream(arr).boxed()
.sorted(Collections.reverseOrder())
.mapToInt(Integer::intValue)
.toArray();
System.out.println(Arrays.toString(arrDesc)); // outputs [6, 5, 4, 3, 2, 1]how to sort array
public static void main(String args[])
{
int [] array = new int[10];
array[0] = ((int)(Math.random()*100+1));
array[1] = ((int)(Math.random()*100+1));
array[2] = ((int)(Math.random()*100+1));
array[3] = ((int)(Math.random()*100+1));
array[4] = ((int)(Math.random()*100+1));
array[5] = ((int)(Math.random()*100+1));
array[6] = ((int)(Math.random()*100+1));
array[7] = ((int)(Math.random()*100+1));
array[8] = ((int)(Math.random()*100+1));
array[9] = ((int)(Math.random()*100+1));
System.out.println(array[0] +" " + array[1] +" " + array[2] +" " + array[3]
+" " + array[4] +" " + array[5]+" " + array[6]+" " + array[7]+" "
+ array[8]+" " + array[9] );
}Copyright © 2021 Codeinu
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