Answers for "how to order an array in java"

3

Arrays.sort() in java

// how to sort an array in java without using sort() method (ascending order)
public class WithoutSortMethod
{
   public static void main(String[] args)
   {
      int temp;
      int[] arrNumbers = {14, 8, 5, 54, 41, 10, 1, 500};
      System.out.println("Before sort: ");
      for(int num : arrNumbers)
      {
         System.out.println(num);
      }
      for(int a = 0; a < arrNumbers.length; a++)
      {
         for(int b = a + 1; b < arrNumbers.length; b++)
         {
            if(arrNumbers[a] > arrNumbers[b])
            {
               temp = arrNumbers[a];
               arrNumbers[a] = arrNumbers[b];
               arrNumbers[b] = temp;
            }
         }
      }
      System.out.println("---------------");
      System.out.println("After sort: ");
      for(int num : arrNumbers)
      {
         System.out.println(num);
      }
   }
}
Posted by: Guest on November-29-2020
1

Arrays.sort() in java

// java sort array of objects
import java.util.Arrays;
public class Employee implements Comparable<Employee>
{
   private String empName; 
   private int empAge;
   public Employee(String name, int age) 
   { 
      this.empName = name; 
      this.empAge = age; 
   }
   @Override 
   public String toString() 
   { 
      return "{" + "name='" + empName + '\'' + ", age=" + empAge + '}'; 
   }
   public String getName() 
   { 
      return empName; 
   }
   public int getAge() 
   { 
      return empAge; 
   }
   @Override 
   public int compareTo(Employee o) 
   { 
      if(this.empAge != o.getAge()) 
      { 
         return this.empAge - o.getAge(); 
      }
      return this.empName.compareTo(o.getName()); 
   }
}
public class SortArrayObjects 
{
   public static void main(String[] args) 
   {
      Employee[] obj = { new Employee("virat", 25), new Employee("dhoni", 20), 
                         new Employee("rohit", 22), new Employee("rahul", 24)};
      Arrays.sort(obj); 
      System.out.println(Arrays.toString(obj));
   }
}
Posted by: Guest on November-29-2020
0

java sort int array

// an array of ints
int[] arr = {1, 2, 3, 4, 5, 6};

// an array of reverse sorted ints
int[] arrDesc = Arrays.stream(arr).boxed()
    .sorted(Collections.reverseOrder())
    .mapToInt(Integer::intValue)
    .toArray();

System.out.println(Arrays.toString(arrDesc)); // outputs [6, 5, 4, 3, 2, 1]
Posted by: Guest on September-01-2020

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