how to use for loop for array in java
// Java program to iterate over an array
// using for loop
import java.io.*;
class GFG {
public static void main(String args[]) throws IOException
{
int ar[] = { 1, 2, 3, 4, 5, 6, 7, 8 };
int i, x;
// iterating over an array
for (i = 0; i < ar.length; i++) {
// accessing each element of array
x = ar[i];
System.out.print(x + " ");
}
}
}arrays with for loops
String[] words = new String[] { "hello", "foo", "bar" };
int[] squares = new int[] { 1, 4, 9, 16 };arrays with for loops
// Search
// Searches through the given array looking
// for the given target. Returns the index number
// of the target if found, or -1 otherwise.
// (classic search-loop example)
public int search(int[] nums, int target) {
// Look at every element
for (int i=0; i<nums.length; i++) {
if (nums[i] == target) {
return i; // return the index where the target is found
}
}
// If we get here, the target was not in the array
return -1;
}arrays with for loops
// Given an array of booleans representing a series
// of coin tosses (true=heads, false=tails),
// returns true if the array contains anywhere within it
// a string of 10 heads in a row.
// (example of a search loop)
public boolean searchHeads(boolean[] heads) {
int streak = 0; // count the streak of heads in a row
for (int i=0; i<heads.length; i++) {
if (heads[i]) { // heads : increment streak
streak++;
if (streak == 10) {
return true; // found it!
}
}
else { // tails : streak is broken
streak = 0;
}
}
// If we get here, there was no streak of 10
return false;
}Copyright © 2021 Codeinu
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