try catch java
public class MyClass {
public static void main(String[ ] args) {
try {
int[] myNumbers = {1, 2, 3, 4, 5, 6};
System.out.println(myNumbers[10]);
} catch (Exception e) {
System.out.println("Something went wrong. check again");
}
}
}try catch exception
First try block try to handle it
if not then catch block will handle it.
Finally block will executed regardless
of the outcometry catch error
// Main program passes in two ints, checks for errors / invalid input
// using template class type T for all variables within functions
#include <iostream>
using namespace std;
template <class T> // make function return type template (T)
void getMin(T val1, T val2)
{
try
{
if (val1 < val2) // if val1 less than return it as min
cout << val1 << " is the minimum\n";
else if (val1 > val2)
cout << val2 << " is the minimum\n";
else
throw 505; // exception error processing when input is invalid
}
catch(T my_ERROR_NUM)
{
cout << "Input is invalid, try again. "; // first part of error message
}
}
template <class T>
void getMax(T val1, T val2) // make function return type template (T)
{
try
{
if (val1 > val2) // if val1 greater then return it as max
cout << val1 << " is the maximum\n\n";
else if (val1 < val2)
cout << val2 << " is the maximum\n\n";
else
throw 505; // exception error processing when input is invalid
}
catch (T random_num)
{
cout << "Error 505!\n\n"; // Second part of error messagee
}
}try catch block
const input = require('readline-sync');
let animals = [{name: 'cat'}, {name: 'dog'}];
let index = Number(input.question("Enter index of animal:"));
try {
console.log('animal at index:', animals[index].name);
} catch(err) {
console.log("We caught a TypeError, but our program continues to run!");
console.log("You tried to access an animal at index:", index);
}
console.log("the code goes on...");Copyright © 2021 Codeinu
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