Answers for "try catch in python"

22

python try catch

try:
  # Dangerous stuff
except ValueError:
  # If you use try, at least 1 except block is mandatory!
  # Handle it somehow / ignore
except (BadThingError, HorrbileThingError) as e:
  # Hande it differently
except:
  # This will catch every exception.
else:
  # Else block is not mandatory.
  # Dangerous stuff ended with no exception
finally:
  # Finally block is not mandatory.
  # This will ALWAYS happen after the above blocks.
Posted by: Guest on June-25-2020
25

try except python

try:
  print("I will try to print this line of code")
except ERROR_NAME:
  print("I will print this line of code if error ERROR_NAME is encountered")
Posted by: Guest on February-01-2020
5

python try except

import sys

try:
    f = open('myfile.txt')
    s = f.readline()
    i = int(s.strip())
except OSError as err:
    print("OS error: {0}".format(err))
except ValueError:
    print("Could not convert data to an integer.")
except:
    print("Unexpected error:", sys.exc_info()[0])
    raise
Posted by: Guest on January-18-2021
11

how to use except statement in python

>>> def divide(x, y):
...     try:
...         result = x / y
...     except ZeroDivisionError:
...         print("division by zero!")
...     else:
...         print("result is", result)
...     finally:
...         print("executing finally clause")
...
>>> divide(2, 1)
result is 2.0
executing finally clause
>>> divide(2, 0)
division by zero!
executing finally clause
>>> divide("2", "1")
executing finally clause
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 3, in divide
TypeError: unsupported operand type(s) for /: 'str' and 'str'
Posted by: Guest on April-28-2020
1

try except python

try:
    Age = int(input("Your Age:- "))
except ValueError:
    print("Age not in Intger form")
Posted by: Guest on June-24-2021
2

python try except

try:
  val = 1/0 
except Exception as e:
  raise Exception('ZeroDivisionError')
Posted by: Guest on January-26-2021

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