Answers for "The parseInt() function parses a string and returns an integer."

6

parseints(str) java

int decimalExample = Integer.parseInt("20"); 
        int signedPositiveExample = Integer.parseInt("+20"); 
        int signedNegativeExample = Integer.parseInt("-20"); 
        int radixExample = Integer.parseInt("20",16); 
        int stringExample = Integer.parseInt("geeks",29); 
  
        // Uncomment the following code to check 
        // NumberFormatException 
  
        //   String invalidArguments = ""; 
        //   int emptyString = Integer.parseInt(invalidArguments); 
        //   int outOfRangeOfInteger = Integer.parseInt("geeksforgeeks",29); 
        //   int domainOfNumberSystem = Integer.parseInt("geeks",28); 
  
        System.out.println(decimalExample); 
        System.out.println(signedPositiveExample); 
        System.out.println(signedNegativeExample); 
        System.out.println(radixExample); 
        System.out.println(stringExample); 

Output:

20
20
-20
32
11670324
Posted by: Guest on May-04-2020
0

Use parseInt() in the convertToInteger function so it converts the input string str into an integer, and returns it.

function convertToInteger(str) {
  return parseInt(str);
}
Posted by: Guest on December-19-2019

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