deserialize json to object c#
dynamic json = Newtonsoft.Json.JsonConvert.DeserializeObject(jsonstring);deserialize json to object c#
dynamic json = Newtonsoft.Json.JsonConvert.DeserializeObject(jsonstring);java deserialize json
private Car parseCar(JsonNode node) {
Car car;
ObjectMapper mapper = new ObjectMapper();
SimpleModule module = new SimpleModule().addDeserializer(Car.class, new CarDeserializer());
mapper.registerModule(module);
organization = mapper.convertValue(node, Car.class);
return car;
}
//deserializer class
public class CarDeserializer extends StdDeserializer<Car> {
public CarDeserializer() {
super(Car.class);
}
@Override
public Car deserialize(JsonParser jsonParser, DeserializationContext deserializationContext) throws IOException {
ObjectMapper objectMapper = new ObjectMapper();
objectMapper.registerModule(new JodaModule());
Car car = new Car();
car.setName(getValueAsText(root, "carName"));
car.setDoorCount(getValueAsInt(root,"doorCount"));
car.setColor(getValueAsText(root,"color"));
car.setType(getValueAsText(root,"type"));
return car;
}
}javascript json deserialize
var objData = JSON.parse(json_string);Copyright © 2021 Codeinu
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