Answers for "json cannot deserialize from object value java"

4

java deserialize json

private Car parseCar(JsonNode node) {
        Car car;
        ObjectMapper mapper = new ObjectMapper();
        SimpleModule module = new SimpleModule().addDeserializer(Car.class, new CarDeserializer());
        mapper.registerModule(module);
        organization = mapper.convertValue(node, Car.class);
        return car;
}

//deserializer class
public class CarDeserializer extends StdDeserializer<Car> {

    public CarDeserializer() {
        super(Car.class);
    }

    @Override
    public Car deserialize(JsonParser jsonParser, DeserializationContext deserializationContext) throws IOException {
        ObjectMapper objectMapper = new ObjectMapper();
        objectMapper.registerModule(new JodaModule());

        Car car = new Car();
        car.setName(getValueAsText(root, "carName"));
        car.setDoorCount(getValueAsInt(root,"doorCount"));
        car.setColor(getValueAsText(root,"color"));
		car.setType(getValueAsText(root,"type"));

        return car;
    }

}
Posted by: Guest on November-05-2020
0

Cannot deserialize the current JSON object (e.g. {“name”:“value”})

using Newtonsoft.Json.Linq;

JObject obj = JObject.Parse(jsonString);
JArray arr = (JArray)obj["logInResult"];
IList<JClass> student= arr.ToObject<IList<JClass>>();

return View(student);
Posted by: Guest on August-03-2021

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