how to check if a number is a palindrome in java

public class StringPalindromeJava { public static void isPalindrome(String str) { String strReverse = new StringBuffer(str).reverse().toString(); // checking for palindrome if(str.equals(strReverse)) { System.out.println(str + " is palindrome string."); } else { System.out.println(str + " is not palindrome string."); } } public static void main(String[] args) { // palindrome java isPalindrome("eye"); isPalindrome("rotator"); } }

import java.util.Scanner; public class Palindrome { public static void main(String args[]) { int num,temp,reverse=0; Scanner input=new Scanner(System.in); num=in.nextInt(); temp=num; //code to reverse the number while(temp!=0) { int d=temp%10; //extracts digit at the end reverse=reverse*10+d; temp/=10; //removes the digit at the end } // 'reverse' has the reverse version of the actual input, so we check if(reverse==num) { System.out.println("Number is palindrome"); } else { System.out.println("Number is not palindrome"); } } }

package test //The function below checks if a string is a palindrome //True = Is a palindrome & False = Not a palindrome public boolean isPalindromString(String text){ String reverse = reverse(text); if(text.equals(reverse)) { return true; } return false; } //This function returns the reverse String of its input. //Ex. if given "hello", it will return "olleh" public String reverse(String input) { if(input == null || input.isEmpty()) { return input; } return input.charAt(input.length()- 1) + reverse (input.substring(0, input.length() - 1)); }

palindrome in java

public class PlaindromeTest1 {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
System.out.println("Enter your words"); // Whats up body? // ?ydob pu stahW
        String word = input.nextLine();

        String reversedWord = "";
        // start from last index number.
        for(int i = word.length()-1; i>=0; i-- ){
           reversedWord += word.charAt(i);
        }
        System.out.println(reversedWord);
        //Level ==> leveL //ey edip adanada pide ye :)
        boolean palindrome = word.equalsIgnoreCase(reversedWord);

        System.out.println(palindrome);

        String str = "Anna";
        String result = "";

        for(int i = str.length()-1; i>=0; i-- ){
            result += str.substring(i, i+1);
            // result += str.charAt(i); // char at de olur
        }
        boolean result1 = str.equalsIgnoreCase(result);
        System.out.println(result1);
    }

Posted by: Guest on June-04-2021

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