Answers for "descending array in java"

8

sort array java

Here’s the java program to sort an array using Arrays.sort() method.

import java.util.Arrays;
public class JavaArraySortMethod
{
   public static void main(String[] args)
   {
      String[] strGiven = {"Great Barrier Reef", "Paris", "borabora", "Florence","tokyo", "Cusco"};
      Arrays.sort(strGiven);
      System.out.println("Output(case sensitive) : " + Arrays.toString(strGiven));
   }
}
Posted by: Guest on October-23-2020
0

java sort array descending

Integer[] cubes = new Integer[] { 8, 27, 64, 125, 256 };
Arrays.sort(cubes, Collections.reverseOrder());

Read more: https://www.java67.com/2016/07/how-to-sort-array-in-descending-order-in-java.html#ixzz6MX60xZLb
Posted by: Guest on May-15-2020
0

how to sort an array

import java.util.Scanner;
public class JavaExample 
{
    public static void main(String[] args) 
    {
    	int count, temp;
    	
    	//User inputs the array size
        Scanner scan = new Scanner(System.in);
        System.out.print("Enter number of elements you want in the array: ");
        count = scan.nextInt();
    
        int num[] = new int[count];
        System.out.println("Enter array elements:");
        for (int i = 0; i < count; i++) 
        {
            num[i] = scan.nextInt();
        }
        scan.close();
        for (int i = 0; i < count; i++) 
        {
            for (int j = i + 1; j < count; j++) { 
                if (num[i] > num[j]) 
                {
                    temp = num[i];
                    num[i] = num[j];
                    num[j] = temp;
                }
            }
        }
        System.out.print("Array Elements in Ascending Order: ");
        for (int i = 0; i < count - 1; i++) 
        {
            System.out.print(num[i] + ", ");
        }
        System.out.print(num[count - 1]);
    }
}
Posted by: Guest on October-13-2020

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