Answers for "max heap"

Java

max heap java

import java.util.PriorityQueue;

public class MaxHeapWithPriorityQueue {

    public static void main(String args[]) {
        // create priority queue
        PriorityQueue<Integer> prq = new PriorityQueue<>(Comparator.reverseOrder());

        // insert values in the queue
        prq.add(6);
        prq.add(9);
        prq.add(5);
        prq.add(64);
        prq.add(6);

        //print values
        while (!prq.isEmpty()) {
            System.out.print(prq.poll()+" ");
        }
    }

}

Posted by: Guest on August-02-2020

Source

heap in java

In Java PriorityQueue can be used as a Heap.

Min Heap
PriorityQueue<Integer> minHeap = new PriorityQueue<>();


Max Heap:
PriorityQueue<Integer> maxHeap = new PriorityQueue<>(Comparator.reverseOrder());

Posted by: Guest on August-31-2020

max heap python

import heapq

Since the built in heapq library is a minheap, multiply your values by -1
and it will function as a max heap. Just remeber that all your numbers 
have been inverted.

Posted by: Guest on August-19-2021

max heap c++ stl;

// C++ program to show that priority_queue is by 
// default a Max Heap 
#include <bits/stdc++.h> 
using namespace std; 

// Driver code 
int main () 
{ 
	// Creates a max heap 
	priority_queue <int> pq; 
	pq.push(5); 
	pq.push(1); 
	pq.push(10); 
	pq.push(30); 
	pq.push(20); 

	// One by one extract items from max heap 
	while (pq.empty() == false) 
	{ 
		cout << pq.top() << " "; 
		pq.pop(); 
	} 

	return 0; 
}

Posted by: Guest on June-03-2020

min max heap java

// min heap: PriorityQueue implementation from the JDK
PriorityQueue<Integer> prq = new PriorityQueue<>();

// max heap: PriorityQueue implementation WITH CUSTOM COMPARATOR PASSED
// Method 1: Using Collections (recommended)
PriorityQueue<Integer> prq = new PriorityQueue<>(Collections.reverseOrder());
// Method 2: Using Lambda function (may cause Integer Overflow)
PriorityQueue<Integer> prq = new PriorityQueue<>((a, b) -> b - a);

Posted by: Guest on December-04-2020

heap

void max_heapify (int Arr[ ], int i, int N)
    {
        int left = 2*i                   //left child
        int right = 2*i +1           //right child
        if(left<= N and Arr[left] > Arr[i] )
              largest = left;
        else
             largest = i;
        if(right <= N and Arr[right] > Arr[largest] )
            largest = right;
        if(largest != i )
        {
            swap (Arr[i] , Arr[largest]);
            max_heapify (Arr, largest,N);
        } 
     }

Posted by: Guest on August-15-2020

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