how to get a character in java in ascii
import java.text.ParseException; import java.util.Arrays; /** * How to convert a String to ASCII bytes in Java * * @author WINDOWS 8 */ public class StringToASCII { public static void main(String args[]) throws ParseException { // converting character to ASCII value in Java char A = 'A'; int ascii = A; System.out.println("ASCII value of 'A' is : " + ascii); // you can explicitly cast also char a = 'a'; int value = (int) a; System.out.println("ASCII value of 'a' is : " + value); // converting String to ASCII value in Java try { String text = "ABCDEFGHIJKLMNOP"; // translating text String to 7 bit ASCII encoding byte[] bytes = text.getBytes("US-ASCII"); System.out.println("ASCII value of " + text + " is following"); System.out.println(Arrays.toString(bytes)); } catch (java.io.UnsupportedEncodingException e) { e.printStackTrace(); } } } Output ASCII value of 'A' is : 65 ASCII value of 'a' is : 97 ASCII value of ABCDEFGHIJKLMNOP is following [65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80] Read more: https://javarevisited.blogspot.com/2015/07/how-to-convert-string-or-char-to-ascii-example.html#ixzz6k2vn7o4y