Answers for "java super method"

java super.var

class Superclass
{
   int num = 100;
}
class Subclass extends Superclass
{
   int num = 110;
   void printNumber(){
	/* Note that instead of writing num we are
	 * writing super.num in the print statement
	 * this refers to the num variable of Superclass
	 */
	System.out.println(super.num);
   }
   public static void main(String args[]){
	Subclass obj= new Subclass();
	obj.printNumber();	
   }
}

super keyword in java

Variables and methods of super class can
be overridden in subclass. 
In case of overriding , a subclass
object call its own variables and methods.
Subclass cannot  access the variables and
methods of superclass because the overridden
variables or methods hides the 
methods and variables of super class.
But still java provides a way to access 
super class members even if 
its members are overridden. Super is
used to access superclass variables, methods, constructors.
Super can be used in two forms :
1) First form is for calling super class constructor.
2) Second one is to call super class variables,methods.
Super if present must be the first statement.

java super.var

class Superclass
{
   int num = 100;
}
class Subclass extends Superclass
{
   int num = 110;
   void printNumber(){
	/* Note that instead of writing num we are
	 * writing super.num in the print statement
	 * this refers to the num variable of Superclass
	 */
	System.out.println(super.num);
   }
   public static void main(String args[]){
	Subclass obj= new Subclass();
	obj.printNumber();	
   }
}

how to use super class method in java

class Parentclass
{
   //no-arg constructor
   Parentclass(){
	System.out.println("no-arg constructor of parent class");
   }
   //arg or parameterized constructor
   Parentclass(String str){
	System.out.println("parameterized constructor of parent class");
   }
}
class Subclass extends Parentclass
{
   Subclass(){
       /* super() must be added to the first statement of constructor 
	* otherwise you will get a compilation error. Another important 
	* point to note is that when we explicitly use super in constructor
	* the compiler doesn't invoke the parent constructor automatically.
	*/
	super("Hahaha");
	System.out.println("Constructor of child class");

   }
   void display(){
	System.out.println("Hello");
   }
   public static void main(String args[]){		
	Subclass obj= new Subclass();
	obj.display();	 
   }
}

super keyword in java

Variables and methods of super class can
be overridden in subclass. 
In case of overriding , a subclass
object call its own variables and methods.
Subclass cannot  access the variables and
methods of superclass because the overridden
variables or methods hides the 
methods and variables of super class.
But still java provides a way to access 
super class members even if 
its members are overridden. Super is
used to access superclass variables, methods, constructors.
Super can be used in two forms :
1) First form is for calling super class constructor.
2) Second one is to call super class variables,methods.
Super if present must be the first statement.

how to use super class method in java

class Parentclass
{
   //no-arg constructor
   Parentclass(){
	System.out.println("no-arg constructor of parent class");
   }
   //arg or parameterized constructor
   Parentclass(String str){
	System.out.println("parameterized constructor of parent class");
   }
}
class Subclass extends Parentclass
{
   Subclass(){
       /* super() must be added to the first statement of constructor 
	* otherwise you will get a compilation error. Another important 
	* point to note is that when we explicitly use super in constructor
	* the compiler doesn't invoke the parent constructor automatically.
	*/
	super("Hahaha");
	System.out.println("Constructor of child class");

   }
   void display(){
	System.out.println("Hello");
   }
   public static void main(String args[]){		
	Subclass obj= new Subclass();
	obj.display();	 
   }
}