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Answers for "lambda in priorityqueue java"

Java
0

java lambda expression in priorityqueue

PriorityQueue<Integer> pq = new PriorityQueue<>((v1, v2) -> (v1 - v2));
Posted by: Guest on August-10-2021
0

java lambda expression in priorityqueue

PriorityQueue<Integer> pq = new PriorityQueue<>((v1, v2) -> (v1 - v2));
Posted by: Guest on August-10-2021

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