armstrong number in java
int c=0,a,temp;
int n=153;//It is the number to check armstrong
temp=n;
while(n>0)
{
a=n%10;
n=n/10;
c=c+(a*a*a);
}
if(temp==c)
System.out.println("armstrong number");
else
System.out.println("Not armstrong number");armstrong number in java
import java.util.Scanner;
public class Armstrong
{
public static void main(String args[])
{
int num,temp,c=0;
Scanner in=new Scanner(System.in);
num=in.nextInt();
temp=num;
while(num!=0)
{
int d=num%10; //extracting last digit
c+=d*d*d;
num/=10; // removing last digit
}
if(temp==c)
{
System.out.println("Number is Armstrong");
}
else
System.out.println("Number is not Armstrong");
}
}Copyright © 2021 Codeinu
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