Answers for "Write a JAVA program to check whether a number is Armstrong or not using methods."

armstrong number in java

int c=0,a,temp;  
    int n=153;//It is the number to check armstrong  
    temp=n;  
    while(n>0)  
    {  
    a=n%10;  
    n=n/10;  
    c=c+(a*a*a);  
    }  
    if(temp==c)  
    System.out.println("armstrong number");   
    else  
        System.out.println("Not armstrong number");

Posted by: Guest on March-11-2020

Code answers related to "Write a JAVA program to check whether a number is Armstrong or not using methods."

Code answers related to "Java"

Java Answers by Framework

Browse Popular Code Answers by Language

Answers for "Write a JAVA program to check whether a number is Armstrong or not using methods."

Code answers related to "Write a JAVA program to check whether a number is Armstrong or not using methods."

Code answers related to "Java"

Java Answers by Framework

Browse Popular Code Answers by Language

Answers for "Write a JAVA program to check whether a number is Armstrong or not using methods."

Code answers related to "Write a JAVA program to check whether a number is Armstrong or not using methods."

Code answers related to "Java"

Java Answers by Framework

Browse Popular Code Answers by Language

Popular Programming Languages

Advertisements

Company

Compilers

Help

Connect with us